If an object were dropped from the same height on the Moon and on the Earth, how long would take to reach the?

6 time as long


( under root 6) times as long


36 times as longIf an object were dropped from the same height on the Moon and on the Earth, how long would take to reach the?
The gravitational acceleration of the moon is 1.63 m/s^2, about 16.7% that of earth's. Because weight is directly dependent upon gravitational acceleration, things on the moon will weigh only 16.7% of which they weigh on the earth.





on earth it's 9.8 m/s^2





u can do the math its not hardIf an object were dropped from the same height on the Moon and on the Earth, how long would take to reach the?
Answer = 6 times as long





An object dropped from a height of four feet on Earth will require an interval of 0.5 seconds before it strikes the floor. The moon's gravitational force is approximately one-sixth that of Earth's attraction, so the same object dropped from the same height on the moon would require 3 seconds of time before striking the lunar surface, or 6 times as long as on Earth.





This experiment has to use items not affected by air resistance, such as a sheet of paper, a tissue, or a balloon. Since Earth possesses an atmosphere, the descent of these objects is considerably slowed by the molecules of air which must be pushed away from the path of the falling article.
t = sqrt(2h/g)


t₂/t₁ = sqrt(g₁/g₂)


g₁/g₂ = 6


t₂/t₁ = sqrt(6)


Earth's gravity is six times stronger than the moon's gravity, so it takes an object sqrt(6) times longer to reach the ground on the moon than on Earth, if the initial height is the same in each case.
gravity on earth is 9.8


gravity on the moon is one sixth that on earth


use maths and sub in the weight of the object and height and you will get the answer