On the moon, acceleration due to gravity is about 1.6m/sec^2. If you drop a rock...?

on the moon with initial velocity 0, what are the formulas for velocity v(t), and distance s(t).





thanks!On the moon, acceleration due to gravity is about 1.6m/sec^2. If you drop a rock...?
v = 1.6t





s(t) = (1/2) * 1.6 * t^2On the moon, acceleration due to gravity is about 1.6m/sec^2. If you drop a rock...?
S= ut + 0.5*g*t^2


Time taken , t is inversely proportional to the square root of accln due to gravity.





t(moon)/t(earth)= [ g(earth)/g(moon)] ^0.5


THerefore t(moon) = t(earth) * 6^0.5





Now V = 0.5* 1.6 *t


s = 0.5*1.6*t^2