If the acceleration of gravity on the moon is 1.62 m/s2 downward, how long does it take the feather to hit the moon's surface?
sAn astronaut drops a feather from 0.7 m above the surface of the moon.?
Since there's no air on the moon you can ignore air resistance.
x = x(0) + v(0)t + 1/2at^2
initially velocity is 0 and we take the point we drop it at to be x = 0.
so
t = sqrt((2x/a))
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment