If the acceleration of gravity on the Moon is 1.62 m/s2, what is the speed of the rock just before it lands?An astronaut on the Moon drops a rock straight downward from a height of 1.00 m.?
u = 0
v = v
a = 1.62
s = 1
v^2 = u^2 + 2as = 0 + 2*1.62
v = sqrt(2*1.62)
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