During a walk on the Moon, an astronaut accidentally drops his camera over a tall cliff. It leaves his hands with zero speed, and after 1.9 s it has attained a velocity of 3.2 m/s downward. How far has the camera fallen after 4.4 s?During a walk on the Moon, an astronaut accidentally drops his camera over a tall cliff.?
For a constantly accelerating object dropped from rest: a = v/t
distance fallen from rest = 1/2 at^2 = 1/2 (v1/t1)t^2
where v1 is the speed at time t1 and t is the final time.During a walk on the Moon, an astronaut accidentally drops his camera over a tall cliff.?
It won't fall. There is no gravity on the moon.
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